How do you solve log y = log (x-1) + 1? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer A. S. Adikesavan Mar 25, 2016 y = 10 (x-1), x > 1. Explanation: Working on common logarithm, y = 10^((log(x-1)+1). 10^(m+n)= 10^m 10^n and 10^(log a)=a. y = (x-1) X 10^1=10(x-1) Here, log(x-1) is defined for x > 1. So, the answer is suject yo x > 1.. Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 3497 views around the world You can reuse this answer Creative Commons License