How do you solve log y = log (x-1) + 1?

1 Answer
Mar 25, 2016

y = 10 (x-1), x > 1.

Explanation:

Working on common logarithm, y = 10^((log(x-1)+1).
10^(m+n)= 10^m 10^n and 10^(log a)=a.
y = (x-1) X 10^1=10(x-1)
Here, log(x-1) is defined for x > 1. So, the answer is suject yo x > 1..