# How do you solve log x + log (x-3)=1?

Dec 6, 2015

$b = 10 R i g h t a r r o w x = \frac{3 + 7}{2} = 5$

#### Explanation:

${\log}_{b} \left[x \left(x - 3\right)\right] = {\log}_{b} b$

$x \left(x - 3\right) = b$

${x}^{2} - 3 x - b = 0$

x = (3 ± sqrt{9 + 4b})/2

Consider $x > 0$ and $x - 3 > 0$