How do you solve #log x - log 8= 3#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Sidharth Oct 28, 2015 #x = 8000# Explanation: #Log x - log 8 = 3# #=>log (x/8) = 3# #=>10^3 = x/8# #=>10^3 * 8 = x/8 *8# #=>1000 * 8 = x# #therefore x = 8000# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 6653 views around the world You can reuse this answer Creative Commons License