How do you solve #log x - log 8= 3#?

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Answer 1 · 2015-10-28T10:31:36

#x = 8000#

#=>log (x/8) = 3#

#=>10^3 = x/8#

#=>10^3 * 8 = x/8 *8#

#=>1000 * 8 = x#