How do you solve $log x - log 10= 14$ ?

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Answer 1 · 2018-03-12T09:19:57

$x=10^15$

We make use of two identities, one - $loga-logb=log(a/b)$ and if $logu=v$ , then $u=10^v$

Using them we can write $logx-log10=14$ as

$log(x/10)=14$

or $x/10=10^14$

i.e. $x=10xx10^14=10^15$

How do you solve log x - log 10= 14log x - log 10= 14?