How do you solve $log x - log 10 = 14$ $log x - log 10= 14$ ?

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How do you solve $log x - log 10 = 14$ $log x - log 10= 14$ ?

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Answer 1 · 2018-03-12T09:19:57

$x = 10^{15}$ $x=10^15$

Explanation:

We make use of two identities, one - $log a - log b = log (\frac{a}{b})$ $loga-logb=log(a/b)$ and if $log u = v$ $logu=v$ , then $u = 10^{v}$ $u=10^v$

Using them we can write $log x - log 10 = 14$ $logx-log10=14$ as

$log (\frac{x}{10}) = 14$ $log(x/10)=14$

or $\frac{x}{10} = 10^{14}$ $x/10=10^14$

i.e. $x = 10 \times 10^{14} = 10^{15}$ $x=10xx10^14=10^15$

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How do you solve $log x - log 10 = 14$ $log x - log 10= 14$ ?

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