# How do you solve log(x + 9) = log4x ?

Nov 18, 2015

$x = 3$

#### Explanation:

For the logs to be equal then what you are taking logs of are also equal.

Write as

$\log \left(x + 9\right) = \log \left(4 x\right) \to x + 9 = 4 x$

$3 x = 9$
$x = 3$