How do you solve #(log_x (7)(log_7 (5)) = 6#? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Bdub Mar 3, 2016 #(log7)/(logx)*(log5)/(log7)=6->log5/logx=6->log_x5=6->x^6=5->x=5^(1/6)=root6(5)# Explanation: Use change of base formula#log_bx=logb/logx# to rewrite each logarithm and then simplify then solve for x Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 1744 views around the world You can reuse this answer Creative Commons License