How do you solve $−log(x) = 5.4$ ?

Question

10518 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-22T06:24:12

$x=e^(-27/10)=x$

After5 the Definition

$log_a(b)=n$ if $a^n=b$
we get

$log(x)=-27/5$
therefore

$x=e^(-27/5)$

Answer 2 · 2018-06-22T06:50:36

$~~3.98*10^-6$

Given: $-log(x)=5.4$

$=>log(x)=-5.4$

Since there is no base, the assumed base used is base $10$ .

So, we get:

$log_10(x)=-5.4$

$x=10^-5.4$ (through logarithm definitions)

$~~3.98*10^-6$

How do you solve −log(x) = 5.4−log(x) = 5.4?