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How do you solve #log(x-5)=-2#?

1 Answer

Jul 18, 2016

#x=5.01#.

Explanation:

By defn. of #log# function, #logt=m iff t=10^m#

#:. log(x-5)=-2 rArr x-5=10^-2=0.01#

#:. x=5+0.01=5.01#.

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