**Answer:**

** 0.637 V**

**Explanation:**

From Ohm's law,

V = IR ................ Equation 1

Where V = Voltage, I = current, R = resistance.

Also

R = Lρ/A........... Equation 2

Where L = Length of the copper wire, ρ = resistivity of the copper wire, A = cross sectional area of the copper wire.

But,

A = πd²/4.................. Equation 2

Where d = diameter.

Substitute equation 2 into equation 1

R = 4Lρ/πd²............... Equation 3

Substitute equation 3 into equation 1

V = I(4Lρ/πd²)........... Equation 4

Given: I = 7.3 A, L = 16 m, d = 2 mm = 0.002 m, π = 3.14,

constant: ρ = 1.72 x 10⁻⁸ Ωm

Substitute into equation 4

V = 7.3(4×16×1.72x10⁻⁸)/(3.14×0.002²)

V = 8.04×10⁻⁶/(1.256×10⁻⁵)

**V = 0.637 V**