How do you solve #log x^3 + log 8 =3#?

1 Answer
Gió
Aug 4, 2015

I found: #x=5#

Explanation:

Supposing your logs with base #10# and considering the property of the sum of logs you can write:
#log_10(x^3*8)=3#
#8x^3=10^3#
#x^3=10^3/8# taking the cube root on both sides you get:
#root3(x^3)=root3(10^3/8)#
So:
#x=10/2=5#

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