# How do you solve log x^2 + log 25 = 2?

The answer is $x = 2$
$\log {x}^{2} + \log 25 = 2 \implies \log 25 {x}^{2} = \log 100 \implies 25 {x}^{2} = 100 \implies {x}^{2} = 4 \implies x = 2 , x = - 2$
But $x > 0$ hence $x = 2$