How do you solve #log x=-2#?

1 Answer
Feb 8, 2016

Since there is no base noted in subscript to the right of the log, this logarithm is in base 10. We can convert directly to exponential form.

Explanation:

#logx = -2#

#x = 10^-2#

#x = 1/(10^2)#

#x = 1/100#

The answer is #x = 1/100#

Practice exercises:

  1. Solve the following logarithmic equations. Round solutions to the nearest hundredth whenever necessary.

a) #log(x + 1) = 1#

b) #log_7(x - 2) = 2#

Good luck!