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How do you solve #log (x-1)^2 = log (-5x-1)#?

1 Answer

Sep 2, 2015

# x = -1 # or # x = -2 #

Explanation:

# log (x-1)^2 = log (-5x-1) #
# x^2-2x+1 = -5x-1 #
# x^2+3x+2 = 0 #
# (x+1)(x+2) = 0 #
# x = -1 # or # x = -2 #

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