How do you solve #log_b(x - 1) + log_b(x + 2) = log_b(8 - 2x)#?
Notice that all the logs are of the same base!
First of all
We can remove the logs since both sides are logarithms of the same base.
This is a simple quadratic equation.
This can be solved by completing the square (or by using the quadratic formula)
However, since you can't take the logarithm of a negative number, x cannot be less than 0. Therefore