# How do you solve Log_b 64 = 6?

${b}^{6} = 64 \to {b}^{6} = {2}^{6} \to {\left({b}^{6}\right)}^{\frac{1}{6}} = {\left({2}^{6}\right)}^{\frac{1}{6}} \to b = 2$ Or
${b}^{6} = 64 \to \sqrt[6]{{b}^{6}} = \sqrt[6]{64} \to b = 2$