How do you solve log_b(5)=0.558?

1 Answer
May 3, 2016

I found b=e^2.8843=17.89~~18

Explanation:

I would try changing base to your log choosing the natural log, i.e., ln:

(ln(5))/(ln(b))=0.558
so rearranging:
ln(b)=(ln(5))/(0.558)=2.8843
now we apply the definition of log to get:
b=e^2.8843=17.89~~18