How do you solve $log_b(5)=0.558$ ?

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Answer 1 · 2016-05-03T14:05:15

I found $b=e^2.8843=17.89~~18$

I would try changing base to your log choosing the natural log, i.e., $ln$ :

$(ln(5))/(ln(b))=0.558$
so rearranging:
$ln(b)=(ln(5))/(0.558)=2.8843$
now we apply the definition of log to get:
$b=e^2.8843=17.89~~18$

How do you solve log_b(5)=0.558log_b(5)=0.558?