How do you solve #log_b(3)=0.381#? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer A. S. Adikesavan May 6, 2016 #b = log 3/0.381=1.2523#, nearly. Explanation: Use # log_b a = log a/log b#. Here., #log_b 3 = log 3/log b=0.381#. So, #log b = log 3/ 0.381=1.2523#, nearly... Answer link Related questions What is the exponential form of #log_b 35=3#? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is #log_b 1#? What are some identity rules for logarithms? What is #log_b b^x#? What is the reciprocal of #log_b a#? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 1324 views around the world You can reuse this answer Creative Commons License