How do you solve #log_9x = 1.5#?

Question

How do you solve #log_9x = 1.5#?

1 Answer

Impact of this question

1273 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-11T12:23:50

I found #x=27#

Explanation:

We can write it trying to manipualte #1.5# into #3/2#:
#log_9(x)=3/2#
we use the definition of log:
#x=9^(3/2)#
and the property of exponents:
#x=sqrt(9^3)#
#x=27#

Science

Math

Humanities

... and beyond

How do you solve #log_9x = 1.5#?

1 Answer

Explanation:

Related questions

Impact of this question