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How do you solve #log_9 x = 1.5#?

1 Answer

Sep 2, 2016

#:. x=27#.

Explanation:

By Defn., #log_b a=m iff a=b^m#.

# :. log_9 x=1.5 rArr 9^(1.5)=x#

#:. x=(3^2)^(1.5)#

#:. x=3^(2xx1.5)#.

#;. x=3^3#.

#:. x=27#.

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