How do you solve #log_8 48-log_8 w=log_8 6#?

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How do you solve #log_8 48-log_8 w=log_8 6#?

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Answer 1 · 2016-10-29T14:07:26

Answer is #w# = 8.

Explanation:

#log_8 48-log_8w=log_8 6#
#:.# #log48/log8-logw/log8=log6/log8#
#:.# #log48-logw=log6#
#:.# #log8*6-logw=log6#
#:.# #log8+log6-logw=log6#
#:. log8-logw=0#
#:.logw=log8#
#:.w=8#. (answer).

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How do you solve #log_8 48-log_8 w=log_8 6#?

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