# How do you solve log 64 = 2logx?

Jun 25, 2018

$x = 8$

#### Explanation:

$\log 64$

= $\log {2}^{6}$

= $6 \log 2$

= $2 \left(3 \log 2\right)$

= $2 \log {2}^{3}$

= $2 \log 8$

But we are given $\log 64 = 2 \log x$

Hence $x = 8$