How do you solve #log_(6)x + log_(6)3 = 2#?
We can start by subtracting
We can apply the logarithm rule
Let's simplify what I have underlined:
Which simplifies to
Further simplifying, we get
Remember, this is the underlined portion of our equation. We have
Since the bases are the same, we now have
All we did was:
- Subtract to get logs on both sides
- Rewrite the expression in a form we can deal with
- Simplify the expression using many exponent properties
- Realized that the bases are the same, so they basically cancel
Hope this helps!