How do you solve # (¼)log_6 (a – 3) – log_6 3 = 0#?

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Answer 1 · 2018-07-26T16:55:33

#a=84#

We have ,

#1/4log_6(a-3)-log_6 3=0#

#=>1/4log_6(a-3)=log_6 3#

#=>log_6(a-3)=4log_6 3to["Multiplying both sides by 4]"#

#=>log_6(a-3)=log_6 3^4to[becauselog_k x^n=nlog_k x]#

#=>log_6(a-3)=log_6 81#

#=>a-3=81#

#=>a=81+3#

#=>a=84#