# How do you solve log(5x + 3) = 0?

$- \frac{2}{5}$
$\log \left(5 x + 3\right) = 0$
$\mathmr{and} , {e}^{\log \left(5 x + 3\right)} = {e}^{0}$
$\mathmr{and} , 5 x + 3 = 1$
Hence, $x = - \frac{2}{5}$