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How do you solve #Log(5(2^x)) = log(3-2^(x+2))#?

1 Answer

A. S. Adikesavan

Apr 22, 2016

#x = log 3/log 2#/

Explanation:

Equating the arguments,

#5( 2^x)=3-2^(x+2 )= 3-2^x2^2 =3-4( 2^x)#

So, #2^x=3# and.

#x log 2 = log 3#
#x=log 3/log 2#.

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