# How do you solve  Log 5 = 2 - Log x?

Feb 27, 2016

$x = {e}^{2} / 5$

#### Explanation:

log5=2−logx

logx=2−log5

$\log x = \log \left({e}^{2}\right) - \log 5$

$\log x = \log \left({e}^{2} / 5\right)$

$x = {e}^{2} / 5$