# How do you solve log(4x-1)=5?

Mar 20, 2016

You first get $\log$s on both sides.

#### Explanation:

Remember that $\log {10}^{5} = 5 \log 10 = 5 \times 1 = 5$
So:
$\log \left(4 x - 1\right) = \log {10}^{5}$

We can now remove the $\log$s:
$\to 4 x - 1 = {10}^{5} = 100000$

Add $1$ to both sides:
$\to 4 x = 100001$

$\to x = \frac{100001}{4} = 25000 \frac{1}{4} \mathmr{and} 25000.25$