How do you solve #log (4k-5)=log(2k-1)#?
1 Answer
Nov 18, 2016
Explanation:
Using the
#color(blue)"laws of logarithms"#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(logx=logyrArrx=y)color(white)(2/2)|)))#
#rArr4k-5=2k-1#
#2k=4rArrk=2#
