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How do you solve #log(3x)=log(5)+log(x-4)#?

1 Answer

Mar 1, 2016

#x=10#

Explanation:

Using the laws of logs we can simplify the right hand side to :

#log(3x)=log[(5)(x-4)]#

#therefore log(3x)=log(5x-20)#

Now take the antilog base 10 on both sides to obtain

#3x=5x-20#

#therefore x=20/2=10#

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