How do you solve #log (3x+5)-log (x-5)=log 8#?

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Answer 1 · 2016-04-09T07:25:03

#=>log((3x+5)/(x-5))=log8#
#=>((3x+5)/(x-5))=8#
#=>(3x+5)=8(x-5)#
#=>8x-40-3x-5=0#
#=>5x=45#
#:. x =9#