How do you solve #log_3x=5#?

1 Answer
KillerBunny
Sep 30, 2016

#243#

Explanation:

Let's think about the meaning of the expression.

#log_3(x)=y# means that, if I want to obtain #x#, I must raise the base #3# to the #y#-th power.

In other words, #y# must be the exponent that we must give to #3# to obtain #x#, or again, #3^y=x#.

In our case, #y=5#, so #log_3(x)=5# means that #x# is the number you obtain by raising #3# to the fifth power, and so #x=3^5#. If you prefer, #x=243#.

Related questions
See all questions in Logarithmic Models
Impact of this question
1308 views around the world
You can reuse this answer
Creative Commons License