# How do you solve log(3x+1)=2?

Aug 21, 2016

$x = 33$

#### Explanation:

By definition if $\log a = b$, we have ${10}^{b} = a$, hence

$\log \left(3 x + 1\right) = 2$

$\Leftrightarrow \left(3 x + 1\right) = {10}^{2}$ or

$3 x + 1 = 100$ or

$3 x = 100 - 1$ or

$3 x = 99$ or

$x = \frac{99}{3} = 33$