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How do you solve # log_3(x^2) - log_3(x+3) =3#?

1 Answer

Dec 20, 2015

#x= (27+-9sqrt5)/2#

Explanation:

LHS= #log_3 ((x^2)/(x+3))#, Hence it is #log_3 ((x^2)/(x+3))#=3

#((x^2)/(x+3))= 3^3 =27#

#x^2 -27x -81=0#

#x= (27+-sqrt (729-324))/2#

#x= (27+-9sqrt5)/2#

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