# How do you solve  Log_ 3 3^(4x-1) = 15?

Dec 15, 2015

$x = 4$

#### Explanation:

Use the following property of logarithms: ${\log}_{a} \left({b}^{c}\right) = c \cdot {\log}_{a} b$

Thus, the equation can be rewritten as

$\left(4 x - 1\right) \left({\log}_{3} 3\right) = 15$

Note that ${\log}_{3} 3 = 1$.

$4 x - 1 = 15$

$x = 4$