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How do you solve $log_3 (2x + 1) = log_3 (x - 4)$ ?

1 Answer

Konstantinos Michailidis

May 7, 2016

We have that

$log_3 (2x + 1) = log_3 (x - 4)=> (2x+1)=(x-4)=>2x-x=-1-4=>x=-5$

But hence it should be $x>4$ there no real solutions.

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