How do you solve log_3 (2x-1) = 3?

Dec 25, 2015

$x = 14$

Explanation:

To undo a logarithm with base $3$, exponentiate both sides with a base of $3$.

${3}^{{\log}_{3} \left(2 x - 1\right)} = {3}^{3}$

$2 x - 1 = 27$

$2 x = 28$

$x = 14$