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How do you solve #log(2x-8)=4#?

1 Answer

Mar 31, 2018

#x={e^4+8}/2 approx 31.3#

Explanation:

(Assuming log base e)

The trick is to rewrite 4 as a logarithm so that the logarithms can be removed. #4=log(e^4)#

#log(2x-8)=4#

#log(2x-8)=log(e^4)#
#2x-8=e^4#

#2x=e^4+8#

#x={e^4+8}/2 approx 31.3#

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