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How do you solve #Log(2x-1)=3#?

1 Answer

Dec 5, 2015

#x=1001/2#

Explanation:

#log(2x-1)=3 -># generally log without base consider as common log so the base is 10

Write in exponential form
#2x-1=10^3#

#2x=1001#
#x=1001/2#

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