# How do you solve log_2(x+2) - log_2x = 3?

$x = \frac{2}{7}$
Using log a - log b = $\log \left(\frac{a}{b}\right)$,
${\log}_{2} \left(\frac{x + 2}{x}\right) = 3$
Inversely, $\left(\frac{x + 2}{x}\right) = {2}^{3} = 8$