# How do you solve Log_(2)X^2-log_(2)x=log_(4)4?

##### 1 Answer
Feb 15, 2016

Firstly, ${\log}_{a} \left(a\right) = 1$.

#### Explanation:

Since now both terms on the left side of the equation have a common base, we can simplify with the rule ${\log}_{a} n - {\log}_{a} m = {\log}_{A} \left(\frac{n}{m}\right)$.

${\log}_{2} \left({x}^{2} / x\right) = 1$

${\log}_{2} \left(x\right) = 1$

Convert to exponential form. The 2 is the base, the 1 the exponent and the x the result.

$x = {2}^{1}$

$x = 2$

So, x = 2.

Hopefully this helps!