# How do you solve #Log_2 (10X + 4) - Log_2 X = 3#?

##### 1 Answer

Jan 5, 2016

No solution.

#### Explanation:

First, simplify using the rule that

#log_2((10X+4)/X)=3#

To undo the logarithm, exponentiate both sides with base

#2^(log_2((10X+4)/X))=2^3#

#(10X+4)/X=8#

Solve for

#10X+4=8X#

#X=-2#

**Warning!** This is an invalid answer. If

If we graph this as a function, the graph should never cross the

graph{ln(10x+4)/ln2-lnx/ln2-3 [-5.64, 22.84, -3.47, 10.77]}