# How do you solve log _16(x - 4) = log _3(3 - x)?

$x = \text{no solution}$
There is no solution to this logarithmic equation. If you try to substitute $x = 2 , 3 , 4 , \text{or}$ $5$ into the equation, you will always end up taking the logarithm of a negative number, which is not possible.
${\log}_{16} \left(x - 4\right) = {\log}_{3} \left(3 - x\right)$
$\textcolor{g r e e n}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} x = \text{no solution} \textcolor{w h i t e}{\frac{a}{a}} |}}}$