How do you solve #log _16(x - 4) = log _3(3 - x)#?

1 Answer
Johnson Z.
Mar 28, 2016

#x="no solution"#

Explanation:

There is no solution to this logarithmic equation. If you try to substitute #x=2,3,4, "or"# #5# into the equation, you will always end up taking the logarithm of a negative number, which is not possible.

#log_16(x-4)=log_3(3-x)#

#color(green)(|bar(ul(color(white)(a/a)x="no solution"color(white)(a/a)|)))#

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