# How do you solve log_(121)x= 2?

$x = 14641$
Let's use both sides of the equation as exponents with a base $121$:
${121}^{{\log}_{121} \left(x\right)} = {121}^{2}$
On the left, by definition of a logarithm we have just an unknown variable $x$:
$x = {121}^{2} = 14641$