How do you solve #log (10-4x)=log(10-3x)#?
1 Answer
Jul 14, 2016
x = 0
Explanation:
Making use of the following fact from
#color(blue)"laws of logarithms"#
#color(red)(|bar(ul(color(white)(a/a)color(black)(logx=logyrArrx=y)color(white)(a/a)|)))#
#rArr10-4x=10-3xrArrx=0#
