How do you solve #log_10 3z=2#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer salamat Jan 12, 2017 #z = 33 1/3# Explanation: #log_"10" 3z = 2# Understand this for easy to remember, #if 100 =10^2#, then #log_"10"100=2# #3z = 10^2# #3z = 100# #z = 100/3# #z = 33 1/3# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 2253 views around the world You can reuse this answer Creative Commons License