How do you solve #log_10 1#?

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How do you solve #log_10 1#?

↳Redirected from "Suppose that I don't have a formula for #g(x)# but I know that #g(1) = 3# and #g'(x) = sqrt(x^2+15)# for all x. How do I use a linear approximation to estimate #g(0.9)# and #g(1.1)#?"

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Answer 1 · 2016-02-03T00:21:34

#log_10 1 = 0#

Explanation:

For any base #b > 0# with #b!=1# we have #log_b 1 = 0#

since #b^0 = 1# for any #b > 0#

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How do you solve #log_10 1#?

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