How do you solve #log (1/100) = log(10^(x+2))#?
1 Answer
Jun 19, 2018
Explanation:
#"using the "color(blue)"law of logarithms"#
#•color(white)(x)logx=logyhArrx=y#
#1/100=10^(x+2)#
#10^(-2)=10^(x+2)#
#"since the bases are equal, equate the exponents"#
#x+2=-2rArrx=-4#
