How do you solve #lnx + ln(x-2) = ln3#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Bdub Apr 21, 2016 #x~~2.45# Explanation: #ln(x(x-2))=ln3# #ln(x^2-2x)=ln3# #x^2-2x-ln3=0# #x=(2+-sqrt(4+4ln3))/2# #x~~2.45 or x~~-0.45# #x~~2.45# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 4333 views around the world You can reuse this answer Creative Commons License