# How do you solve ln y = 2x + 4?

$y = {e}^{2 x + 4}$
Assuming the goal is to isolate $y$, we can do so by raising both sides as a power of $e$, cancelling the natural logarithm:
${e}^{\ln} \left(y\right) = {e}^{2 x + 4}$
$y = {e}^{2 x + 4}$