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How do you solve #ln x + ln 3x = 12#?

1 Answer

Vinícius Ferraz

Dec 6, 2015

#x = + sqrt(3)/3 e^6#

Explanation:

#ln (x * 3x) = 12#

#x * 3x = e^12#

#x^2 = 1/3 e^12#

#x = ± sqrt(3)/3 e^6#

But x > 0.

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